How x² + 2x + 5 Becomes 2x + 2

Kurtis Weissnat

Differentiate x squared plus 2x plus 5 to 2x plus 2, and see how the derivative measures change.

A curve, not a snapshot

Consider the function

f(x)=x2+2x+5f(x) = x^{2} + 2x + 5

For each input x, you get a height on a smooth curve. The value alone says where you are. The derivative says how that height is changing as x moves.

Differentiate term by term

Power rule: d/dx (xⁿ) = n · xⁿ⁻¹. Constants vanish under differentiation.

ddx(x2)=2xddx(2x)=2ddx(5)=0\begin{aligned} \frac{d}{dx}(x^{2}) &= 2x \\ \frac{d}{dx}(2x) &= 2 \\ \frac{d}{dx}(5) &= 0 \end{aligned}

Add them:

f′(x)=2x+2f'(x) = 2x + 2

So the messy-looking quadratic collapses into a simple line that tracks slope.

What 2x + 2 reveals

At a point x = a, the number f'(a) = 2a + 2 is the instantaneous rate of change of f.

Here f'(x) = 2(x + 1) = 0 when x = -1. Near that point the quadratic bottoms out; elsewhere the sign of 2x + 2 tells you whether f grows or shrinks as x increases.

Change, made precise

The derivative is a limit of average rates:

f′(x)=limh→0⁡f(x+h)−f(x)hf'(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h}

For our f, that limit evaluates to 2x + 2. Average rise-over-run becomes an exact slope—change without needing a finite step size.

Takeaway

Differentiating x² + 2x + 5 to 2x + 2 is not a magic rewrite. It extracts the curve’s local rate of change and hands it back as a new function you can read, graph, and reason with.

Katie Haus

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